【求教】自己写了一个3*4矩阵键盘，按键显示相应数值的程序，不能实现功能，求指导。

#include

unsigned char ledchar[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e};   //共阳极数码管

unsigned char keybuf[3][4]={{0,0,0,0},{0,0,0,0},{0,0,0,0}};      //按键值缓存数组

sbit IN_1=P2^6;                    //3行

sbit IN_2=P2^5;

sbit IN_3=P2^4;

sbit OUT_1=P2^3;               //4列

sbit OUT_2=P2^2;

sbit OUT_3=P2^1;

sbit OUT_4=P2^0;

void main()

{

    unsigned char i,j;

    unsigned char backup[3][4]={{0,0,0,0}，{0,0,0,0},0,0,0,0}};     //按键值备份

    EA=1;

    TMOD=1;

    TH0=0xFC;                    //1ms扫描一次按键

    TL0=0x67;

    ET0=1;

    TR0=1;

    P0=ledchar[0];

    while(1)    

    {

        for(i=0;i<=3;i++)

        {

            for(j=0;j<=4;j++)

            {

                if(backup[i][j]!=keybuf[i][j])                        //有按键按下

              {

                    if(backup[i][j]==1)                               //按键按下并弹起

                  {

                        P0=ledchar[i*4+j+1];

                   }

                    backup[i][j]=keybuf[i][j];

               }

            }

        }

    }

}

void InterruptTimer0() interrupt 1

{    

    static unsigned char keyin=0;

    static unsigned char keyout[3][4]={ {0x00, 0x00, 0x00, 0x00},{0x00, 0x00, 0x00, 0x00},{0x00, 0x00, 0x00, 0x00},   };    

    static unsigned char i=0;

    TH0=0xFC;

    TL0=0x67;

    keyout[keyin][0]=(keyout[keyin][0]<<1)|OUT_1;                       //消抖

    keyout[keyin][1]=(keyout[keyin][1]<<1)|OUT_2;

    keyout[keyin][2]=(keyout[keyin][2]<<1)|OUT_3;

    keyout[keyin][3]=(keyout[keyin][3]<<1)|OUT_4;

    for(i=0;i<=4;i++)                                                                  //判断键值，0为弹起，1为按下

    {

        if((keyout[keyin][i]&0x0f)==0x00)

        {

            keybuf[keyin][i]=0;

        }

        else if((keyout[keyin][i]&0x0f)==0x0f)

        {

            keybuf[keyin][i]=1;

        }

    }

keyin++;

keyin=keyin&0x02;                                              //keyin值为0，1，2

switch(keyin)

{

    case 0:IN_1=1;IN_2=0;IN_3=0;break;

    case 1:IN_1=0;IN_2=1;IN_3=0;break;

    case 2:IN_1=0;IN_2=0;IN_3=1;break;   

     default : break;}

}