一:
输入
AC90V-264V
输出:5V@500mA
设:f=50KHz,Dmax=0.5 Ton=10us
电路结构:RCC反激
Ipk=K*Pout/VDCin(min)(对于反激电路K=5.5)
=5.5*5*0.5/(90*1.41)=0.10A
Lp=VDCin(min)*Ton/Ipk
=90*1.41*10us/0.1
=12.69mH
二:输入
AC:200V-264V
其它条件同上
Ipk=K*Pout/VDCin(min)(对于反激电路K=5.5)
5.5*5*0.5/(200*1.41)=0.05A
Lp=VDCin(min)*Ton/Ipk
=200*1.41*10us/0.05=56mH
用EE13的变压器电感取这两种值都太离谱了.不知道怎么解决?请大家帮忙.
峰值电流我计算错了吗?
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