请教各位DX.单端反激开关变压器参数搞不懂啊(芯片是L6561)!
各位DX及七年老师:L6561Z在单端反激开关变压器的参数几个见图中间所标示的是怎样换算出来的啊!
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1. Design Specifications:
- Mains voltage range: VACmin = 88 Vac, VACmax = 264 Vac
- Minimum mains frequency: fL = 50 Hz
- DC Output Voltage: Vout = 15 V
- Maximum output current: Iout = 2A
- Maximum 2fL output ripple: DVo = 1V peak-to-peak
2. Pre-design Choices:
- Minimum switching frequency: fswmin = 25 kHz
- Reflected voltage: VR = 100V ??此反射电压怎么来的啊
- Leakage inductance overvoltage: DV =70V
- Expected efficiency: h = 85%
3. Preliminary Calculations:
AN1059 APPLICATION NOTE
- Maximum Input Peak Voltage: VPKmin = VACmin × Ö``2 = 264 × Ö``2 = 373V
- Maximum Output Power: Pout = Vout × Iout = 15 × 2 = 30W
- Maximum Input Power: Pin =
Pout
h
× 100 =
30
85
× 100 = 35.3W
- Peak-to-reflected Voltage Ratio: Kv =
VPKmin
VR
=
120
100
= 1.2
- Characteristic functions value: F1(1.2)=0.343; F2(1.2)=0.254; F3(1.2)=0.209; F5(1.2)=0.108???
这里的F1 F2 F3 F5又是从那里换算来的哪!
4. Operating Conditions:
- Peak Primary Current: IPKp =
2 × Pin
VPKmin × F2(Kv)
=
2 × 35.3
120 × 0.254
= 2.32A
- RMS Primary Current: IRMSp = IPKp × Ö``F2`(`Kv)
3
= 2.32 × Ö``0.`2`54
3
= 0.675A
- Peak Secondary current: IPKs =
2 × Iout
Kv × F2(Kv)
=
2 × 2
1.2 × 0.254
= 13.1A
- RMS Secondary Current: IRMSs = IPKs × Ö``Kv` × ```
F3(Kv)
3
= 13.1 × Ö``1.`2 `× ```
0.209
3
= 3.79A
5. Transformer:
- Primary inductance: Lp =
VPKmin
(1 + Kv) × fswmin × IPKp
=
120
(1 + 1.2) × 25 × 103 × 2.32
= 940mH
- Primary-to-secondary turns ratio: n =
VR
(Vout + Vf)
=
100
15 + 0.6
= 6.41
- Mains voltage range: VACmin = 88 Vac, VACmax = 264 Vac
- Minimum mains frequency: fL = 50 Hz
- DC Output Voltage: Vout = 15 V
- Maximum output current: Iout = 2A
- Maximum 2fL output ripple: DVo = 1V peak-to-peak
2. Pre-design Choices:
- Minimum switching frequency: fswmin = 25 kHz
- Reflected voltage: VR = 100V ??此反射电压怎么来的啊
- Leakage inductance overvoltage: DV =70V
- Expected efficiency: h = 85%
3. Preliminary Calculations:
AN1059 APPLICATION NOTE
- Maximum Input Peak Voltage: VPKmin = VACmin × Ö``2 = 264 × Ö``2 = 373V
- Maximum Output Power: Pout = Vout × Iout = 15 × 2 = 30W
- Maximum Input Power: Pin =
Pout
h
× 100 =
30
85
× 100 = 35.3W
- Peak-to-reflected Voltage Ratio: Kv =
VPKmin
VR
=
120
100
= 1.2
- Characteristic functions value: F1(1.2)=0.343; F2(1.2)=0.254; F3(1.2)=0.209; F5(1.2)=0.108???
这里的F1 F2 F3 F5又是从那里换算来的哪!
4. Operating Conditions:
- Peak Primary Current: IPKp =
2 × Pin
VPKmin × F2(Kv)
=
2 × 35.3
120 × 0.254
= 2.32A
- RMS Primary Current: IRMSp = IPKp × Ö``F2`(`Kv)
3
= 2.32 × Ö``0.`2`54
3
= 0.675A
- Peak Secondary current: IPKs =
2 × Iout
Kv × F2(Kv)
=
2 × 2
1.2 × 0.254
= 13.1A
- RMS Secondary Current: IRMSs = IPKs × Ö``Kv` × ```
F3(Kv)
3
= 13.1 × Ö``1.`2 `× ```
0.209
3
= 3.79A
5. Transformer:
- Primary inductance: Lp =
VPKmin
(1 + Kv) × fswmin × IPKp
=
120
(1 + 1.2) × 25 × 103 × 2.32
= 940mH
- Primary-to-secondary turns ratio: n =
VR
(Vout + Vf)
=
100
15 + 0.6
= 6.41
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@lb0577
1.DesignSpecifications:-Mainsvoltagerange:VACmin=88Vac,VACmax=264Vac-Minimummainsfrequency:fL=50Hz-DCOutputVoltage:Vout=15V-Maximumoutputcurrent:Iout=2A-Maximum2fLoutputripple:DVo=1Vpeak-to-peak2.Pre-designChoices:-Minimumswitchingfrequency:fswmin=25kHz-Reflectedvoltage:VR=100V??此反射电压怎么来的啊-Leakageinductanceovervoltage:DV=70V-Expectedefficiency:h=85%3.PreliminaryCalculations:AN1059APPLICATIONNOTE-MaximumInputPeakVoltage:VPKmin=VACmin×Ö``2=264×Ö``2=373V-MaximumOutputPower:Pout=Vout×Iout=15×2=30W-MaximumInputPower:Pin=Pouth×100=3085×100=35.3W-Peak-to-reflectedVoltageRatio:Kv=VPKminVR=120100=1.2-Characteristicfunctionsvalue:F1(1.2)=0.343;F2(1.2)=0.254;F3(1.2)=0.209;F5(1.2)=0.108???这里的F1F2F3F5又是从那里换算来的哪!4.OperatingConditions:-PeakPrimaryCurrent:IPKp=2×PinVPKmin×F2(Kv)=2×35.3120×0.254=2.32A-RMSPrimaryCurrent:IRMSp=IPKp×Ö``F2`(`Kv)3=2.32×Ö``0.`2`543=0.675A-PeakSecondarycurrent:IPKs=2×IoutKv×F2(Kv)=2×21.2×0.254=13.1A-RMSSecondaryCurrent:IRMSs=IPKs×Ö``Kv`×```F3(Kv)3=13.1×Ö``1.`2`×```0.2093=3.79A5.Transformer:-Primaryinductance:Lp=VPKmin(1+Kv)×fswmin×IPKp=120(1+1.2)×25×103×2.32=940mH-Primary-to-secondaryturnsratio:n=VR(Vout+Vf)=10015+0.6=6.41
原文件如下:500) {this.resized=true; this.width=500; this.alt='这是一张缩略图,点击可放大。\n按住CTRL,滚动鼠标滚轮可自由缩放';this.style.cursor='hand'}" onclick="if(!this.resized) {return true;} else {window.open('http://u.dianyuan.com/bbs/u/43/1152664792.gif');}" onmousewheel="return imgzoom(this);">
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@lb0577
原文件如下:[图片]500){this.resized=true;this.width=500;this.alt='这是一张缩略图,点击可放大。\n按住CTRL,滚动鼠标滚轮可自由缩放';this.style.cursor='hand'}"onclick="if(!this.resized){returntrue;}else{window.open('http://u.dianyuan.com/bbs/u/43/1152664792.gif');}"onmousewheel="returnimgzoom(this);">
再附完整官方提供l6561单端反激的应用资料1152664920.rar
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